如图以rt Abc的三边为斜边分别�外作等腰直角三角形．若斜边ab=$sqrt{2}$则图中阴影部分的面积为 A．1b．$frac Sketch Coloring Page

如图以rt Abc的三边为斜边分别�外作等腰直角三角形．若斜边ab=$sqrt{2}$则图中阴影部分的面积为 A．1b．$frac Template

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sketch #4306 The burning watermelon!

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sketch #921 comics ufo

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sketch #5159 Frank Briones Silvia Haynes

tomski如图以rt abc的三边为斜边分别�外作等腰直角三角形．若斜边ab=$sqrt{2}$则图中阴影部分的面积为 a．1b．$frac coloring

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示 1 如图�分别以直角三角形ABC三边为 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

如图已知Rt ABC中∠ACB=90°∠B＞∠A在 ABC内找一点E使得 EBC和 ABC相似小聪的做法是取AB边上的中线CD sketch template

三角形“四心”有关性质及证明（内心篇）知乎 sketch template

如图Rt ABC中已知∠C=90°∠B=48°点D在边BC上BD=2CD把Rt ABC绕点D逆时针旋转m度后如果点B恰好落在初始 sketch template

如图在Rt ABC中∠ACB=90°CD⊥AB于D设AC=bBC=aCD=hAB=c下面有3个�题11a2 1b2 sketch template

如图�，Rt ABC中，∠ACB=90°，点D为边AC上一点，DE⊥AB于点E，点M为BD中点，点N为CM中点，CM的延长线交AB于点F sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

题目如图在Rt ABC中∠A=90°AB=6cmAC=8cm以斜边BC上距离B点6cm的点P为中心把这个三角形按逆时针方�旋转 sketch template

如图，在Rt ABC中，分别以三角形的三条边为边�外作正方形，面积分别记为S1，S2，S3．若S1=9，S2=16，则S3的值为（） A7 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在正方形ABCD中EC=2BE三角形 BOC的面积是3平方米求阴影部分的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图直角三角形ABC的三边分别为3cm4cm5cm将这个直角三角形以一条直角边所在的直线为轴旋转一�求所形成的立体图形的体积——青夏 sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

如图CD是Rt ABC斜边上的高则图中相似三角形的对数有 A0对B1对C2对D3对题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图在Rt ABC中∠B=90°AB=6cmBC=8cm点D从点A出�以1cm/s的速度运动到点C停止．作DE⊥AC交边AB或BC于 sketch template

如图所示已知Rt ABC中AH为斜边BC上的高M为BC中点O为 ABC外心OB交AH于D．求证AD=2DH．题目和参考答案——青 sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图以Rt ABC的直角边AC和斜边AB为边分别作Rt ADC和正方形ABEF再以AD作正方形ADGH．已知∠ACB=90°正方形 sketch template

如图在等腰Rt ABC中∠BAC=90°AB=ACBC=2$sqrt{2}$点D是AC边上一动点连接BD以AD为直径的圆交BD sketch template

如图1P为Rt ABC所在平面内任一点∠ACB=90°M为AB的中点．操作以PAPC为邻边作平行四边形PADC连接PM并延长到点E sketch template

如图在Rt ABC中∠C=90°．1根据要求用尺规作图过点C作斜边AB边上的高CD垂足为D不写作法只保留作图痕迹2证明 sketch template

如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB=4则图中阴影部分的面积为 ．题目和参考答案——青夏教育精英家教�—— sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

定理“直角三角形中30°角所对直角边是斜边的一半 的其中一个逆定理是三角形中如果一直角边是斜边的一半一直角边是斜边的一半那么这条直角边 sketch template

题目如图 在Rt ABC中∠ACB＝90°AC＝6BC＝8将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使 sketch template

如图所示在等腰Rt ABC中AC=BC以斜边AB为一边作等边 ABD使点CD在AB的同侧再以CD为一边作等边 ECD使点CE在 sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

如图等腰Rt ABC的直角边ABAC分别与圆O相切于点EDAD=3DC=5直线FG与ACBC分别交于点FG且∠CFG=60 sketch template

如图分别以Rt ABC三边为边�外作三个正方形其面积分别用S1S2S3表示容易得出S1S2S3之间有的关系式．题目和参考答案 sketch template

如图以AD为直径的半圆O经过Rt ABC的斜边AB的两个端点交直角边AC于点E．BE是半圆弧的三等分点弧BE的长为则图中阴影部分的 sketch template

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